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Answer :
Let's go through each question step-by-step.
How many standard deviations away from the mean is a value of 79?
- Given the mean [tex]\mu = 145[/tex] and standard deviation [tex]\sigma = 22[/tex].
- The formula for the z-score is [tex]z = \frac{X - \mu}{\sigma}[/tex], where [tex]X[/tex] is the value.
- So, [tex]z = \frac{79 - 145}{22} = \frac{-66}{22} = -3[/tex].
- Interpretation: The value 79 is three standard deviations below the mean.
- Correct answer: B. It is three standard deviations below the mean.
Approximately what percent of SHS students have a height greater than 140 cm?
- Mean height [tex]\mu = 150[/tex] cm and [tex]\sigma = 10[/tex] cm.
- Find the z-score for 140 cm: [tex]z = \frac{140 - 150}{10} = -1[/tex].
- Using the standard normal distribution, about 84% of data lies above a z-score of -1.
- Correct answer: B. 84%
Find the area above [tex]z = 2.56[/tex].
- From z-tables, [tex]P(Z < 2.56) \approx 0.9946[/tex].
- Thus, area above [tex]z = 2.56[/tex] is [tex]1 - 0.9946 = 0.0054[/tex].
- Correct answer: A. 0.0052
Find the area of the shaded region of the given figure.
- Unfortunately, without the figure, it's not possible to identify the shaded region's area.
If the weights are normally distributed, what is the z-score of a woman with a weight of 70?
- Assuming mean and standard deviation are provided (need these values to calculate), this step needs these values for a correct z-score calculation.
What is the z-score of a woman with a weight of 50 kg?
- This requires the mean and standard deviation.
How many kilograms will correspond to the z score of 0.5 of the weight of a woman?
- Again, the specific mean and standard deviation are needed to calculate the exact weight.
Approximate age range in which 68% of people retire (Philippines)?
- Mean age [tex]\mu = 70[/tex] years, [tex]\sigma = 5[/tex] years.
- 68% of data within one standard deviation: [tex]70 - 5 = 65[/tex] to [tex]70 + 5 = 75[/tex].
- Correct answer: A. 65 – 75 years
What percent of the population is considered genius with IQ [tex]\geq 140[/tex]?
- Using [tex]\mu = 100[/tex], [tex]\sigma = 15[/tex].
- Find [tex]z[/tex] for 140: [tex]z = \frac{140 - 100}{15} = 2.67[/tex].
- From z-tables: [tex]P(Z > 2.67) \approx 0.38%[/tex].
- Correct answer: D. 0.38%
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