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A toy rocket is launched vertically upward from the ground. If its initial speed is 8.93 m/s, with what speed will it strike the ground?

Answer :

Final answer:

The toy rocket, given no air resistance, will strike the ground with the same speed it was launched with, 8.93 m/s. This is due to the principle of conservation of energy.

Explanation:

This problem involves the concepts of physics, specifically the principles of projectile motion. When the rocket is launched and when it strikes the ground, it will have the same speed, ignoring the air resistance. This is because of the principle of conservation of energy.

To calculate it, we can use the formula: V = √(2gh + v₁²). Where g represents acceleration due to gravity (approx. 9.81m/s²), h is the change in height (in this case, 0 since the rocket strikes back at the ground level) and v₁ is the initial speed.

Substitute the given values into the equation: √(2*9.81*0 + (8.93 m/s)²), and the result will again be 8.93 m/s. Therefore, the rocket will strike the ground with the same speed it was launched, which is 8.93 m/s.

Learn more about Projectile Motion here:

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