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A volume of 10.0L of gas at a temperature of 5c is cooled to a temperature of 85C at constant pressure what is the new volume of gas

Answer :

I don't know how 5°C cooled to 85°C but the answer would be 12.878L

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Rewritten by : Barada

Answer:

At constant pressure the new volume of gas is 12.878 L.

Explanation:


Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. So the ratio between volume and temperature will always have the same value:

[tex]\frac{V}{T} =k[/tex]


where the temperature is expressed in degrees kelvin (° K)


Then, when considering the two situations 1 and 2, keeping the amount of gas and the temperature constant, the relationship must be met:

[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]

In this case, you know:

  • V1= 10 L
  • T1= 5 +273 = 278°K (where 0°C=273°K)
  • V2= ?
  • T2= 85 + 273 = 358°K

Replacing:

[tex]\frac{10}{278} =\frac{V2}{358}[/tex]

Solving:

[tex]V2=\frac{10}{278} *358[/tex]

V2=12.878 L

At constant pressure the new volume of gas is 12.878 L.