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Answer :
To find the best predicted temperature when a bug is chirping at a rate of 3000 chirps per minute, we can use linear regression. It seems that the provided data is not formatted properly, so we will make some assumptions to proceed.
Let's assume that the bug chirping rate (x) is our independent variable, and the temperature (y) is the dependent variable. We can use the given data points (chirp rate and temperature) to create a linear regression equation.
Step 1: Calculate the slope (m) and y-intercept (b) of the regression line using the given data points.
Step 2: Once we have the regression equation in the form y = mx + b, we can substitute the chirp rate (x) of 3000 chirps per minute into the equation to find the predicted temperature (y).
For part a), substitute x = 3000 into the regression equation and round the result to 3 decimal places.
For part b), the predicted value would be the result obtained from part a).
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