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A section is 1 mile by 1 mile. How wide is a four-acre easement that runs along the western edge of a section?

(Note: One acre contains 43,560 square feet.)

Answer :

Final answer:

The four-acre easement that runs along the western edge of a section is approximately 33 feet wide. This calculation is derived by first converting the acreage to square feet and then dividing by the length of the section (1 mile or 5280 feet)

Explanation:

Firstly, we need to convert the acres into square feet. One acre is 43,560 square feet, so four acres would be 4 * 43,560 = 174,240 square feet. A section is 1 mile by 1 mile and 1 mile is 5280 feet. So, the total area of the section is 5280 * 5280 = 27,878,400 square feet.

The easement runs along the western edge, that is, it's a type of long, narrow rectangle that is 1 mile long (or 5280 feet), but we don't know its width. We know its area, though, which is 174,240 square feet. To find the width, we need to divide the area of the easement by its length. So, we have 174,240 / 5280 = "approximately 33 feet". Hence, the width of the four-acre easement that runs along the western edge of a section is roughly 33 feet.

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Final answer:

The four-acre easement that runs along the western edge of a section, which is 1 mile by 1 mile, is 33 feet wide.

Explanation:

To calculate the width of the four-acre easement that runs along the western edge of a section, we first need to understand the total area we're working with. An acre is 43,560 square feet. Therefore, four acres would be four times that, or 174,240 square feet.

Since the easement runs along the edge of the section, it must also be 1 mile long, the same length as the edge of the section. There are 5,280 feet in a mile. Thus, to find the width of the easement in feet, we must divide the total square footage (174,240 sq ft) by the length of the easement (5,280 feet).

Doing the calculation, 174,240 divided by 5,280 equals 33. So, the four-acre easement is 33 feet wide.

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