Answer :

The fluency of the 14.5-MeV neutrons in water at the point of interest is 5.892 × [tex]10^{11}[/tex] particles/m².

Fluency is a measure of the number of particles passing through a unit area. It is expressed in units of particles per square meter.

To calculate the fluence, we can use the relationship between fluency and kerma:

Φ = K / E

Where

Φ = fluence

K = kerma

E = average energy of the particles.

In this case, the kerma is given as 1.37 Gy, and the energy of the neutrons is 14.5 MeV. However, the energy needs to be converted to joules for consistent units. To convert MeV to joules, we can use the conversion factor 1 MeV = 1.602 × [tex]10^{-13[/tex]J.

So, the average energy of the neutrons (E) can be calculated as:

E = 14.5 MeV × 1.602 × [tex]10^{-13[/tex] J/MeV

E = 2.3249 × [tex]10^{-12[/tex]J

Now we can calculate the fluence:

Φ = 1.37 Gy / 2.3249 × [tex]10^{-12[/tex]J

Φ ≈ 5.892 × [tex]10^{11}[/tex] particles/m².

Therefore, the fluency of the 14.5-MeV neutrons in water at the point of interest is 5.892 × [tex]10^{11}[/tex] particles/m².

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A field of 14.5-MeV neutrons deposits a kerma of 1.37 Gy at a point of interest in water. What is the fluence?

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