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Which line is perpendicular to a line that has a slope of [tex]-\frac{5}{6}[/tex]?

A. Line JK
B. Line LM
C. Line NO
D. Line PQ

Answer :

To determine which line is perpendicular to a line with a slope of [tex]\(-\frac{5}{6}\)[/tex], we need to calculate the perpendicular slope.

The slope of a line that is perpendicular to another line is found by taking the negative reciprocal of the original line's slope. Here's how you can do that:

1. Start with the original slope, which is [tex]\(-\frac{5}{6}\)[/tex].
2. Find the reciprocal of this slope. The reciprocal of [tex]\(-\frac{5}{6}\)[/tex] is [tex]\(-\frac{6}{5}\)[/tex].
3. Take the negative of this reciprocal. Since the original slope is negative, the negative reciprocal will be positive. Therefore, the perpendicular slope is [tex]\(\frac{6}{5}\)[/tex].

Now, let's express [tex]\(\frac{6}{5}\)[/tex] as a decimal to compare more easily:
[tex]\[
\frac{6}{5} = 1.2
\][/tex]

Hence, a line with a slope of 1.2 is perpendicular to the line with a slope of [tex]\(-\frac{5}{6}\)[/tex]. To answer the question, you would select the line (e.g., line LM, line NO, etc.) that has a slope of 1.2 from the given options.

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