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Answer :
Sure! Let's solve the problem step-by-step.
Sammie took [tex]$25 out of her checking account, and after taking the money out, she had $[/tex]100 left. We are trying to find how much money Sammie had in her account before she took the [tex]$25 out.
Let's use the variable \( c \) to represent the amount of money Sammie originally had in her account. We can set up an equation to model the situation. Since she withdrew $[/tex]25, you will subtract [tex]$25 from her original amount \( c \), leaving her with $[/tex]100. So, the equation to represent this situation is:
[tex]\[ c - 25 = 100 \][/tex]
Now, to solve for [tex]\( c \)[/tex], we need to get [tex]\( c \)[/tex] by itself on one side of the equation. We can do this by adding [tex]$25 to both sides of the equation.
So, let's add 25 to both sides:
\[ c - 25 + 25 = 100 + 25 \]
Simplifying the left side gives us:
\[ c = 125 \]
So, Sammie originally had $[/tex]125 in her account before she took out the $25.
Sammie took [tex]$25 out of her checking account, and after taking the money out, she had $[/tex]100 left. We are trying to find how much money Sammie had in her account before she took the [tex]$25 out.
Let's use the variable \( c \) to represent the amount of money Sammie originally had in her account. We can set up an equation to model the situation. Since she withdrew $[/tex]25, you will subtract [tex]$25 from her original amount \( c \), leaving her with $[/tex]100. So, the equation to represent this situation is:
[tex]\[ c - 25 = 100 \][/tex]
Now, to solve for [tex]\( c \)[/tex], we need to get [tex]\( c \)[/tex] by itself on one side of the equation. We can do this by adding [tex]$25 to both sides of the equation.
So, let's add 25 to both sides:
\[ c - 25 + 25 = 100 + 25 \]
Simplifying the left side gives us:
\[ c = 125 \]
So, Sammie originally had $[/tex]125 in her account before she took out the $25.
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