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Calculate the magnitude of the average force (in Newtons) on a bumper that collapses 0.21 m while bringing a 1,550.82 kg car to rest from an initial speed of 19.77 m/s.

(Note: Your answer should be a raw number, possibly between several thousand to hundreds of thousands, such as 123456.7.)

Answer :

The average force on the bumper can be calculated using the formula: Average force = (mass × change in velocity) / time

To find the time, we can use the formula:
Change in velocity = acceleration × time
Since the car is coming to rest, the final velocity is 0 m/s. Therefore, the change in velocity is equal to the initial velocity.

Let's calculate the time first:
Change in velocity = 19.77 m/s - 0 m/s
Change in velocity = 19.77 m/s

We know the initial velocity and the change in velocity, but we don't know the acceleration or the time. However, we do have the distance traveled by the bumper:
Distance = (1/2) × acceleration × time^2
Since we know the distance and we need to solve for time, let's rearrange the equation:
time^2 = (2 × distance) / acceleration


We can substitute the change in velocity for the acceleration:
time^2 = (2 × distance) / change in velocity
time^2 = (2 × 0.21 m) / 19.77 m/s
time^2 = 0.021 m / 19.77 m/s
time^2 = 0.001063

Now, let's solve for time:
time = √(0.001063)
time ≈ 0.0326 s

Now we can calculate the average force:
Average force = (mass × change in velocity) / time
Average force = (1550.82 kg × 19.77 m/s) / 0.0326 s
Calculating this, we get:
Average force ≈ 94177.99 N

Therefore, the magnitude of the average force on the bumper is approximately 94178 N.

To know more about final velocity visit:

brainly.com/question/34167933

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