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Answer :
Final answer:
The concentration of the HCl solution is calculated to be 0.297 M. Thus, none of the given options is correct.
Explanation:
Given the titration of 25.0 mL of HCl with 66.9 mL of 0.111 M NaOH, we have the balanced equation:
NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)
The reaction shows that NaOH and HCl react on a 1:1 molar basis.
We can calculate the moles of NaOH used in the titration:
Moles of NaOH = Volume (L) x Molarity (M)
Moles of NaOH = 0.0669 L x 0.111 M
Moles of NaOH = 0.00743.
Since the amount of HCl is equal to the amount of NaOH that reacted, we have 0.00743 moles of HCl.
To find the concentration of HCl, we use the formula:
Concentration of HCl = Moles of HCl / Volume of HCl solution (L)
Concentration of HCl = 0.00743 moles / 0.025 L
Concentration of HCl = 0.2972 M, which rounds off to 0.297 M.
Hence, the concentration of the HCl solution is 0.297 M.
Therefore, none of the given options is correct.
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