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Answer :
Final answer:
The student wants to calculate the coefficient of viscosity of water flowing through a capillary tube. Using fluid dynamics principles and specifically, the concept of capillary action and Poiseuille's law, which governs flow rate in a tube, we can form an equation to calculate the viscosity using given parameters such as fluid density, flow rate, tube dimensions, and contact angle.
Explanation:
The subject of this question is the principle of fluid dynamics and more specifically, the phenomenon of capillary action, and how it relates to the viscosity of water in a capillary tube. This falls within the realm of Physics.
From the provided question, we can see that the flow rate (Q) of the water is given as 0.8 litre/5 minutes which can be converted to meters cubed per second (m3/s). Using Poiseuille's law for the laminar flow of an incompressible fluid through a tube, which states that the flow rate is directly proportional to the pressure difference and inversely proportional to the viscosity of the fluid, we can formulate an equation to solve for the coefficient of viscosity.
It's important to note that the height h of the liquid inside the capillary tube relative to the surface of the liquid outside the tube, as well as the radius r of the tube, are key variables in this calculation. With a known density p of the liquid (water in this case), and the standard acceleration due to gravity g being 9.8 m/s2, we have all the necessary parameters to solve the question.
Since the water molecules are strongly attracted to the tube's material and spread out completely on the surface, this corresponds to a contact angle of 0°. Inserting these values and isolating for the unknown viscosity, one can calculate the coefficient of viscosity of the water flowing through the capillary tube.
Learn more about Viscosity here:
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