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Answer :
Final answer:
The current through the 0.500 H inductor connected to a 60.0 Hz, 480 V AC source is approximately 2.55 A.
Explanation:
The current through a 0.500 H inductor connected to a 60.0 Hz, 480 V AC source can be found using Ohm's law. The inductive reactance (XL) of an inductor is given by the equation XL = 2πfL, where f is the frequency and L is the inductance. In this case, f = 60.0 Hz and L = 0.500 H. Substituting these values into the equation, XL = 2π(60.0 Hz)(0.500 H) = 188.5 Ω.
Using Ohm's law, we can now calculate the current (I) through the inductor. Ohm's law states that I = V/XL, where V is the voltage. In this case, V = 480 V. Substituting these values into the equation, I = 480 V / 188.5 Ω = 2.55 A.
Therefore, the current through the 0.500 H inductor connected to a 60.0 Hz, 480 V AC source is approximately 2.55 A.
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