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Answer :
Final answer:
There are approximately 3.06 grams of oxygen (O) in 35.8 grams of Cu(NO3)2.
Explanation:
To calculate the grams of oxygen (O) in 35.8 grams of Cu(NO3)2, we need to use the molar mass of Cu(NO3)2 and the molar mass of oxygen.
The molar mass of Cu(NO3)2 is 187.55 g/mol, as calculated by adding the atomic masses of each element: Cu (63.55 g/mol) + N (14.01 g/mol) + 3O (16.00 g/mol).
Now, set up a proportion:
(35.8 g Cu(NO3)2) / (187.55 g Cu(NO3)2) = (x g O) / (16.00 g O)
Cross-multiplying,
35.8 g Cu(NO3)2 * 16.00 g O = 187.55 g Cu(NO3)2 * x g O
Simplifying,
x g O = (35.8 g Cu(NO3)2 * 16.00 g O) / 187.55 g Cu(NO3)2
Calculating this expression,
x g O ≈ 3.06 g O
Therefore, there are approximately 3.06 grams of oxygen (O) in 35.8 grams of Cu(NO3)2.
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