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Answer :
To prepare 500 mL of 1.69 M NH₃(aq) from 15 M NH₃(aq), 56.33 mL of the 15 M NH₃(aq) should be diluted with enough water to make a total volume of 500 mL.
To prepare a solution of 1.69 M NH₃(aq) from 15 M NH₃(aq) in a total volume of 500 mL, we can use the formula M¹V¹ = M₂V₂. Solving for V¹, we get V¹ = (M₂V₂) / M¹ = (1.69 M x 500 mL) / 15 M = 56.33 mL. Therefore, we need to dilute 56.33 mL of the 15 M NH₃(aq) with enough water to make a total volume of 500 mL to prepare the desired 1.69 M NH₃(aq) solution for the stockroom.
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