High School

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2) If This, Then That

4. The equation [tex]4(x-2)=100[/tex] is a true equation for a particular value of [tex]x[/tex]. Explain why [tex]2(x-2)=50[/tex] is also true for the same value of [tex]x[/tex].

5. To solve the equation [tex]7.5d=2.5d[/tex], Lin divides each side by [tex]2.5d[/tex], and Elena subtracts [tex]2.5d[/tex] from each side.

a. Will both moves lead to the solution? Explain your reasoning.

b. What is the solution?

Answer :

Sure! Let's go through each part of the question step-by-step.

### 4. Explain why [tex]\(2(x-2)=50\)[/tex] is true for the same value of [tex]\(x\)[/tex] in the equation [tex]\(4(x-2)=100\)[/tex].

To begin, let's solve the first equation [tex]\(4(x-2) = 100\)[/tex] to find the value of [tex]\(x\)[/tex]:

1. Distribute the 4:
[tex]\(4(x - 2) = 4x - 8\)[/tex]

2. Set the equation equal to 100:
[tex]\(4x - 8 = 100\)[/tex]

3. Add 8 to both sides to isolate the term with [tex]\(x\)[/tex]:
[tex]\(4x = 108\)[/tex]

4. Divide both sides by 4 to solve for [tex]\(x\)[/tex]:
[tex]\(x = \frac{108}{4}\)[/tex]
[tex]\(x = 27\)[/tex]

Now, let's check if [tex]\(2(x-2) = 50\)[/tex] is true for [tex]\(x = 27\)[/tex]:

1. Substitute [tex]\(x = 27\)[/tex] into the equation [tex]\(2(x-2)\)[/tex]:
[tex]\(2(27 - 2)\)[/tex]

2. Simplify inside the parentheses:
[tex]\(2(25)\)[/tex]

3. Multiply:
[tex]\(50\)[/tex]

This means that for [tex]\(x = 27\)[/tex], [tex]\(2(x-2) = 50\)[/tex] is also a true statement.

### 5. Solving the equation [tex]\(7.5d = 2.5d\)[/tex]

a. Will both moves lead to the solution?

- Lin's method was to divide both sides by [tex]\(2.5d\)[/tex]:

This approach assumes [tex]\(d \neq 0\)[/tex] and simplifies to [tex]\(3 = 1\)[/tex], which is incorrect. This method does not lead to a valid solution because we cannot divide by zero.

- Elena's method was to subtract [tex]\(2.5d\)[/tex] from each side:

[tex]\[
7.5d - 2.5d = 2.5d - 2.5d \\
5d = 0
\][/tex]

This results in [tex]\(d = 0\)[/tex], which is the correct solution.

b. What is the solution?

Given both methods, only Elena's approach correctly identifies the solution:

- The solution is: [tex]\(d = 0\)[/tex]

Therefore, the moves made by Lin won't lead to the correct solution, but Elena's method will yield the correct value of [tex]\(d\)[/tex].

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