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How many grams are in 10.0 mEq of [tex]$Ca^{2+}$[/tex]?

Answer :

Final answer:

To find the number of grams in 10.0 mEq of Ca2+, calculate the mass of one equivalent of calcium and convert to milliequivalents. One equivalent of Ca2+ is 20.04 grams per mole, so 10 mEq is 200.4 mg, which is equivalent to 0.2004 grams.

Explanation:

To calculate the number of grams in 10.0 mEq of Ca2+, we'll first need to understand the concept of milliequivalents. One milliequivalent (mEq) is one-thousandth of an equivalent, which represents a certain number of moles of charge, based on the valency of the ion. Calcium has a valency of 2, so 1 equivalent of Ca2+ is equal to its molar mass (40.08 g/mol) divided by its valency (2).

We calculate 1 mEq of Ca2+ as follows:

(40.08 g/mol) ÷ 2 = 20.04 g/equiv

Therefore, 1 mEq of Ca2+ is 20.04 mg. To find out the grams in 10.0 mEq of Ca2+, we multiply 20.04 mg by 10:

20.04 mg/mEq × 10 mEq = 200.4 mg

To convert milligrams to grams, we remember there are 1000 milligrams in a gram:

200.4 mg ÷ 1000 = 0.2004 grams

Thus, there are 0.2004 grams in 10.0 mEq of Ca2+.

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