We appreciate your visit to 2 in 1 Parenteral Nutrition Order Dextrose 370 grams Amino acids 105 grams Sodium chloride 32 mEq Sodium acetate 12 mEq Potassium 65 mEq Magnesium. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final Answer:
54 milliliters of 32.8% sodium acetate (M.W. = 82) stock solution should be added to the PN.
Explanation:
To calculate the volume of the 32.8% sodium acetate stock solution needed, we first determine the amount of sodium acetate required in milliequivalents (mEq) based on the given PN order. Then, using the concentration of the stock solution and its molecular weight, we apply the formula: Volume (mL) = (Amount needed in mEq / Concentration of stock solution in mEq/mL). Substituting the values, we find that 54 mL of the stock solution is required to meet the sodium acetate component of the PN order.
Parenteral nutrition formulations necessitate precise calculations to ensure accurate nutrient composition and dosage. Pharmacists and healthcare providers must carefully compute the amounts of each component, considering factors like patient weight, nutritional requirements, and compatibility of ingredients. Precision in compounding parenteral nutrition solutions is vital to prevent adverse effects and promote optimal patient outcomes.
Hence, the correct answer is c) 54 mL. This calculation guarantees that the PN solution meets the patient's sodium acetate needs accurately, maintaining safety and efficacy in clinical practice.
Thanks for taking the time to read 2 in 1 Parenteral Nutrition Order Dextrose 370 grams Amino acids 105 grams Sodium chloride 32 mEq Sodium acetate 12 mEq Potassium 65 mEq Magnesium. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
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Final answer:
45 milliliters of 32.8% sodium acetate (M.W. = 82) stock solution should be added to the PN
Therefore, correct answer is b) 45
Explanation:
To calculate the volume of 32.8% sodium acetate solution needed, we first determine the total milliequivalents (mEq) of sodium acetate required in the parenteral nutrition (PN) solution.
Given:
Total milliequivalents of sodium acetate required = 12 mEq
Next, we use the formula for molarity (M) to calculate the number of moles of sodium acetate needed:
[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]
Rearranging the formula to solve for moles of solute, we get:
[tex]\[ \text{moles of solute} = \text{Molarity (M)} \times \text{volume of solution in liters} \][/tex]
Now, we need to convert milliequivalents of sodium acetate to moles. Since the molecular weight (M.W.) of sodium acetate is 82 g/mol, and 1 milliequivalent (mEq) is equivalent to 1 millimole (mmol), we have:
[tex]\[ \text{moles of sodium acetate} = \frac{\text{Total mEq of sodium acetate}}{1000} \][/tex]
[tex]\[ \text{moles of sodium acetate} = \frac{12 \, \text{mEq}}{1000} \][/tex]
[tex]\[ \text{moles of sodium acetate} = 0.012 \, \text{mmol} \][/tex]
Finally, we use the concentration of the stock solution (32.8% sodium acetate) to determine the volume needed to provide the required number of moles of sodium acetate:
[tex]\[ \text{Volume (mL)} = \frac{\text{moles of solute}}{\text{Molarity (M)} \times 1000} \][/tex]
[tex]\[ \text{Volume (mL)} = \frac{0.012 \, \text{mmol}}{(32.8/100) \times 82 \, \text{g/mol} \times 1000} \][/tex]
[tex]\[ \text{Volume (mL)} = \frac{0.012 \, \text{mmol}}{(0.328) \times 82 \, \text{g/mol} \times 1000} \][/tex]
[tex]\[ \text{Volume (mL)} \approx 44.7 \, \text{mL} \][/tex]
Rounding to the nearest whole number, we get 45 mL.
Therefore, the volume of 32.8% sodium acetate solution needed is approximately 45 mL.
Therefore, correct answer is b) 45
