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Find the slopes of the lines [tex] l_1 [/tex] and [tex] l_2 [/tex] defined by the given points. Then determine whether [tex] l_1 [/tex] and [tex] l_2 [/tex] are parallel, perpendicular, or neither.

Points for [tex] l_1: (9, -1) [/tex] and [tex] (6, -4) [/tex]

Points for [tex] l_2: (6, -3) [/tex] and [tex] (9, -6) [/tex]

Part 1 of 3:

The slope of [tex] l_1 [/tex] is [tex] \square [/tex].

Answer :

To find the slope of line [tex]\( l_1 \)[/tex] using the given points [tex]\((9, -1)\)[/tex] and [tex]\((6, -4)\)[/tex], we will use the formula for calculating the slope between two points. The slope [tex]\( m \)[/tex] of a line through points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is calculated by:

[tex]\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\][/tex]

Let's apply this formula:

- For line [tex]\( l_1 \)[/tex], the points are [tex]\((9, -1)\)[/tex] and [tex]\((6, -4)\)[/tex].
- Here, [tex]\( x_1 = 9 \)[/tex], [tex]\( y_1 = -1 \)[/tex], [tex]\( x_2 = 6 \)[/tex], and [tex]\( y_2 = -4 \)[/tex].

Let's plug these values into the slope formula:

[tex]\[
m = \frac{-4 - (-1)}{6 - 9} = \frac{-4 + 1}{6 - 9} = \frac{-3}{-3}
\][/tex]

Simplifying this expression gives:

[tex]\[
m = 1.0
\][/tex]

Thus, the slope of line [tex]\( l_1 \)[/tex] is [tex]\( 1.0 \)[/tex].

Now, you can input this value into the solution for the slope of [tex]\( l_1 \)[/tex].

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