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How many students must gather to guarantee a 63% chance of two of them having the same last 4 digits of their OSU ID number (assuming OSU ID numbers are chosen uniformly)?

A. 141
B. 6300
C. 10000

Answer :

Final answer:

To calculate the number of students needed to guarantee a 63% chance of two of them having the same last 4 digits of their OSU ID number, we can use the concept of the Birthday Paradox.

Explanation:

To calculate the number of students needed to guarantee a 63% chance of two of them having the same last 4 digits of their OSU ID number, we can use the concept of the Birthday Paradox. First, we determine the probability that two students do NOT have the same last 4 digits.

Let's assume there are n students. The probability that two students have different last 4 digits is (9999/10000) * (9998/10000) * ... * ((9999 - n + 1)/10000).

Therefore, to find the number of students needed to guarantee a 63% chance, we need to calculate the minimum value of n when the probability calculated above is less than or equal to 0.37.

Learn more about Probability here:

https://brainly.com/question/22962752

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