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Calculate the heat required to raise 25.6 g of water from 25.5 °C to 97.6 °C. The specific heat capacity of water is 4.18 J/g°C.

Answer :

Final answer:

To calculate the Specific Heat required to raise the temperature of the water, we use the formula q = mcΔT where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. With a mass of 25.6 g, specific heat capacity of 4.18 J/g °C, and a temperature change of 72.1°C, approximately 7716 J of heat is needed.

Explanation:

The amount of heat required to raise the temperature of a substance is calculated using the formula: q = mcΔT, where q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

In this case, the mass of the water (m) is 25.6 g, the specific heat capacity of water (c) is 4.18 J/g °C, and the change in temperature (ΔT) is 97.6°C - 25.5°C = 72.1°C.

Substituting these values into the formula gives: q = (25.6 g) * (4.18 J/g °C) * (72.1°C) = 7715.744 J. Therefore, approximately 7716 J of heat is required to raise the temperature of 25.6 g of water from 25.5 °C to 97.6 °C.

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