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Answer :
Given that Tank A has leaked 1/16 of a gallon in 1/12 minute, then in 1 minute, Tank A has leaked
[tex] \frac{1}{16} \div \frac{1}{12} = \frac{1}{16} \times12= \frac{3}{4} \ gallons[/tex]
Given that Tank B has leaked 3/80 of a gallon in 1/30 minute, then in 1 minute, Tank A has leaked
[tex] \frac{3}{80} \div \frac{1}{30} = \frac{3}{80} \times30= \frac{9}{8} \ gallons.[/tex]
Thus, in 1 minute tank A has leaked less than 1 gallon while tank B has leaked more than 1 gallon.
Therefore, Tank B is leaking faster.
[tex] \frac{1}{16} \div \frac{1}{12} = \frac{1}{16} \times12= \frac{3}{4} \ gallons[/tex]
Given that Tank B has leaked 3/80 of a gallon in 1/30 minute, then in 1 minute, Tank A has leaked
[tex] \frac{3}{80} \div \frac{1}{30} = \frac{3}{80} \times30= \frac{9}{8} \ gallons.[/tex]
Thus, in 1 minute tank A has leaked less than 1 gallon while tank B has leaked more than 1 gallon.
Therefore, Tank B is leaking faster.
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