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Yeast converts glucose to ethanol and carbon dioxide during anaerobic fermentation as depicted in the simple chemical equation below:

\[ \text{glucose} \rightarrow \text{ethanol} + \text{carbon dioxide} \]

If 97.7 g of carbon dioxide is produced, what mass of ethanol is produced?

Answer :

Final answer:

In anaerobic fermentation, yeast converts glucose into ethanol and carbon dioxide. The mass of ethanol produced when 97.7g of carbon dioxide is produced can be calculated using the molar mass ratio between the two compounds.

Explanation:

In anaerobic fermentation, yeast converts glucose into ethanol and carbon dioxide. The balanced chemical equation for this process is: glucose ⟶ ethanol + carbon dioxide. To find the mass of ethanol produced when 97.7 g of carbon dioxide is produced, we need to determine the molar mass ratio between carbon dioxide and ethanol. The molar mass of carbon dioxide (CO2) is 44.01 g/mol, while the molar mass of ethanol (C2H5OH) is 46.07 g/mol. By using the molar mass ratio and the given mass of carbon dioxide, we can calculate the mass of ethanol produced.

To do this, we set up a proportion: (mass of ethanol)/(mass of carbon dioxide) = (molar mass of ethanol)/(molar mass of carbon dioxide). Plugging in the values, we get: (mass of ethanol)/97.7 g = 46.07 g/mol / 44.01 g/mol. Solving for the mass of ethanol, we find: mass of ethanol = (97.7 g)(46.07 g/mol) / (44.01 g/mol) = 102.79 g.

Therefore, approximately 102.79 grams of ethanol is produced when 97.7 grams of carbon dioxide is produced in anaerobic fermentation.

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