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Rewritten by : Barada
Answer:
(C) 14.83
Step-by-step explanation:
From the given figure, we have
[tex]DF=6, FE=16 and {\angle}D=90^{\circ}[/tex]
Now, using the Pythagoras theorem, we get
[tex](FE)^2=(DE)^2+(DF)^2[/tex]
Substituting the given values, we get
[tex](16)^2=(DE)^2+(6)^2[/tex]
[tex]256=(DE)^2+36[/tex]
[tex]220=(DE)^2[/tex]
[tex]14.83=DE[/tex]
Therefore, the value of DE is 14.83.
Hence, option C is correct.
