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Two lamps illuminate a screen equally.

The first lamp has an intensity of 99.9 cd and is 6.5 m from the screen. The second lamp is 11 m from the screen.

What is the intensity of the second lamp?

Answer :

The intensity of the second lamp, which is 11 m from the screen, is approximately 27.19 cd.

The intensity of the second lamp, we can use the inverse square law for light.

The inverse square law states that the intensity of light is inversely proportional to the square of the distance from the source.

We can calculate the intensity of the second lamp by setting up the following equation: (99.9 cd) / (6.5 m)^2 = (intensity of second lamp) / (11 m)^2

The intensity of light is inversely proportional to the square of the distance from the source. So, to find the intensity of the second lamp, we can use the inverse square law.

The intensity of the first lamp is 99.9 cd at a distance of 6.5 m, so we can find the intensity of the second lamp at a distance of 11 m using the formula:

Intensity1/Intensity2 = (Distance2/Distance1)^2

99.9/Intensity2 = (11/6.5)^2

Intensity2 = (99.9 * 6.5^2)/11^2

The intensity of the second lamp is approximately 27.19 cd.

To know more about equation visit:

https://brainly.com/question/649785

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