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The pressure at a depth of 100 ft in the Great Salt Lake is 46 psig. What is the specific weight of the lake water if it is constant?

Answer :

The specific weight of the Great Salt Lake water, given a pressure of 46 psig at 100 feet depth, is 66.24 lb/ft³.

To determine the specific weight of the Great Salt Lake water, we need to use the formula for pressure due to the depth of a fluid:

Pressure = (specific weight) x (depth)

Here, the given pressure at 100 ft depth is 46 psig (pounds per square inch gauge). The conversion factor for 100 feet to inches is:

  • 100 ft × 12 inches/ft = 1200 inches

Given that 1 psi = 144 lb/ft², converting 46 psig to lb/ft²:

  • 46 psig × 144 lb/ft²/psi = 6624 lb/ft²

Using the formula:

  • 6624 lb/ft² = (specific weight) x 100 ft

Solving for specific weight:

  • Specific weight = 6624 lb/ft² / 100 ft = 66.24 lb/ft³

Thus, the specific weight of the Great Salt Lake water is 66.24 lb/ft³.

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