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Julie has a 20-gallon fish tank full of water that she needs to move from one room to another. She pours out all the water. The fish tank is a right rectangular prism.

- The fish tank weighs 225 pounds when it is filled with water.
- The dimensions of the water inside the fish tank are 30 inches by 12 inches by 12 inches.
- 1 cubic foot of water weighs 62.4 pounds.

Enter the weight of the fish tank when it is empty, to the nearest pound.

Answer :

To find the weight of the empty fish tank, follow these steps:

1. Understand the Problem:
- We have a fish tank with dimensions 30 inches long, 12 inches wide, and 12 inches high.
- The tank weighs 225 pounds when filled with water.
- Our goal is to find out how much the tank weighs when it's empty.

2. Calculate the Volume of Water in the Tank:
- The volume of the tank is calculated using the formula for a rectangular prism: Volume = length × width × height.
- First, convert the dimensions from inches to feet. There are 12 inches in a foot, so for each dimension:
- Length: 30 inches = 30/12 feet = 2.5 feet
- Width: 12 inches = 12/12 feet = 1 foot
- Height: 12 inches = 12/12 feet = 1 foot

- Volume in cubic feet = 2.5 feet × 1 foot × 1 foot = 2.5 cubic feet

3. Calculate the Weight of the Water:
- We know that 1 cubic foot of water weighs 62.4 pounds.
- Therefore, the weight of water in the tank is: 2.5 cubic feet × 62.4 pounds/cubic foot = 156 pounds.

4. Find the Weight of the Empty Tank:
- The total weight of the tank when full is 225 pounds. This includes the weight of both the tank and the water.
- To find the weight of the empty tank, subtract the weight of the water from the total weight:
- Weight of empty tank = Total weight - Weight of water
- Weight of empty tank = 225 pounds - 156 pounds = 69 pounds

So, the weight of the empty fish tank is 69 pounds.

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