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Answer :
Final answer:
The pH of the 0.250 M solution that is 2.31% ionized is 2.24.
Explanation:
To calculate the pH of a solution, we need to determine the concentration of hydrogen ions (H+). In this case, we have a 0.250 M solution that is 2.31% ionized. This means that 2.31% of the solute has dissociated into ions.
To find the concentration of H+ ions, we can multiply the initial concentration of the solution (0.250 M) by the ionization percentage (2.31% or 0.0231).
Concentration of H+ ions = 0.250 M x 0.0231 = 0.005775 M
Now that we have the concentration of H+ ions, we can calculate the pH using the formula:
pH = -log[H+]
Substituting the concentration of H+ ions into the formula:
pH = -log(0.005775) = 2.24
Learn more about calculating the ph of a solution here:
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