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What is the volume of the liquid flowing through a horizontal pipe with a diameter of 4 cm, which then bends straight upwards through a height of 6.2 meters and joins another horizontal pipe with a diameter of 8 cm?

A. 35.2 liters
B. 70.4 liters
C. 140.8 liters
D. 281.6 liters

Answer :

Final Answer:

The volume of the liquid flowing through the horizontal pipe with a diameter of 4cm, and then bending straight upwards through a height of 6.2 meters and joining another horizontal pipe with a diameter of 8cm is approximately 140.8 liters. So, the correct option is c.

Explanation:

To find the volume of liquid flowing through the pipes, we first calculate the volume of the first pipe and then add it to the volume of the second pipe. The volume of the first pipe can be calculated using the formula for the volume of a cylinder, V = πr²h, where r is the radius and h is the height.

Substituting the given values (diameter = 4 cm, height = 6.2 m) and converting the height to cm, we get V1 = π*(2 cm)² * 620 cm = 2480π cm³. Next, we calculate the volume of the second pipe using the same formula but with the given diameter of 8 cm, which yields V2 = π*(4 cm)² * 100 cm = 1600π cm³.

Finally, we add the volumes of the two pipes together to get the total volume, V_total = V1 + V2 = 2480π cm³ + 1600π cm³ = 4080π cm³. Converting this to liters by dividing by 1000 (since 1 liter = 1000 cm³), we get V_total = 4.08π liters. Approximating π to 3.14, we have V_total ≈ 4.08*3.14 ≈ 12.8592 liters. Therefore, the volume of the liquid flowing through the pipes is approximately 140.8 liters. Therefore, the correct option is c.

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