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Answer :
To solve this question, let's break it down into parts:
1. Heterozygous Male (Ww) x Homozygous Recessive Female (ww):
The male's genotype is Ww, which means he can contribute either a W or a w. The female's genotype is ww, so she can only contribute a w.
Let's see the possible combinations of their offspring:
- Male contributes W, Female contributes w: Ww (heterozygous)
- Male contributes w, Female contributes w: ww (homozygous recessive)
If you consider all possible combinations, you'll get:
[tex]\[
\begin{tabular}{|c|c|c|}
\hline & w & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{tabular}
\][/tex]
This table shows that out of four possible outcomes, two are Ww (heterozygous). Hence, the chance that the offspring will be heterozygous is 50%.
2. Heterozygous (Ww) x Homozygous Dominant (WW):
Now, we're considering a cross between a heterozygous (Ww) individual and a homozygous dominant (WW) individual.
Let's see the possible combinations:
- Male contributes W, Female contributes W: WW (homozygous dominant)
- Male contributes w, Female contributes W: Ww (heterozygous)
We can fill a Punnett square to visualize these combinations:
[tex]\[
\begin{tabular}{|c|c|c|}
\hline & W & W \\
\hline w & Ww & Ww \\
\hline W & WW & WW \\
\hline
\end{tabular}
\][/tex]
In this situation, none of the offspring will be homozygous recessive (ww) since there is no possibility of producing an offspring with only recessive alleles. Therefore, the probability of having a homozygous recessive offspring is 0%.
In conclusion, the chance of having heterozygous offspring in the first cross is 50%, and the chance of having homozygous recessive offspring in the second cross is 0%.
1. Heterozygous Male (Ww) x Homozygous Recessive Female (ww):
The male's genotype is Ww, which means he can contribute either a W or a w. The female's genotype is ww, so she can only contribute a w.
Let's see the possible combinations of their offspring:
- Male contributes W, Female contributes w: Ww (heterozygous)
- Male contributes w, Female contributes w: ww (homozygous recessive)
If you consider all possible combinations, you'll get:
[tex]\[
\begin{tabular}{|c|c|c|}
\hline & w & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{tabular}
\][/tex]
This table shows that out of four possible outcomes, two are Ww (heterozygous). Hence, the chance that the offspring will be heterozygous is 50%.
2. Heterozygous (Ww) x Homozygous Dominant (WW):
Now, we're considering a cross between a heterozygous (Ww) individual and a homozygous dominant (WW) individual.
Let's see the possible combinations:
- Male contributes W, Female contributes W: WW (homozygous dominant)
- Male contributes w, Female contributes W: Ww (heterozygous)
We can fill a Punnett square to visualize these combinations:
[tex]\[
\begin{tabular}{|c|c|c|}
\hline & W & W \\
\hline w & Ww & Ww \\
\hline W & WW & WW \\
\hline
\end{tabular}
\][/tex]
In this situation, none of the offspring will be homozygous recessive (ww) since there is no possibility of producing an offspring with only recessive alleles. Therefore, the probability of having a homozygous recessive offspring is 0%.
In conclusion, the chance of having heterozygous offspring in the first cross is 50%, and the chance of having homozygous recessive offspring in the second cross is 0%.
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