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Mikala initially launches a toy rocket from a height of 3 feet above the ground. After 2 seconds, the rocket reaches its highest point of 11 feet and then returns to the ground.

1. Create a model that can be used to determine the height of the toy rocket at a given time. Define your variables and show your work or explain how your equation models the situation.

2. Use the model to determine at what time the toy rocket will land on the ground. Show your work or explain your answer.

Enter your answers and explanations in the box.

Answer :

  • Given the vertex, the model is given by:

[tex]y = -2x^2 + 8x + 3[/tex]

  • Using the model above, it is found that it lands on the ground after 4.35 seconds.

The equation of a quadratic function of vertex (h,k) is given by:

[tex]y = a(x - h)^2 + k[/tex]

The vertex is the maximum point, which is (2,11), hence [tex]h = 2, k = 11[/tex]. Then:

[tex]y = a(x - 2)^2 + 11[/tex]

The initial height is of 3 feet, then when [tex]x = 0, y = 3[/tex], and this is used to find a.

[tex]y = a(x - 2)^2 + 11[/tex]

[tex]3 = 4a + 11[/tex]

[tex]4a = -8[/tex]

[tex]a = -\frac{8}{4}[/tex]

[tex]a = -2[/tex]

Then:

[tex]y = -2(x - 2)^2 + 11[/tex]

In standard format, the model is:

[tex]y = -2x^2 + 8x - 8 + 11[/tex]

[tex]y = -2x^2 + 8x + 3[/tex]

It hits the ground when [tex]y = 0[/tex], so:

[tex]-2x^2 + 8x + 3 = 0[/tex]

[tex]2x^2 - 8x - 3 = 0[/tex]

Which has coefficients [tex]a = 2, b = -8, c = -3[/tex]. So

[tex]\Delta = b^2 - 4ac = (-8)^2 - 4(2)(-3) = 88[/tex]

[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{8 + sqrt{88}}{4} = 4.35[/tex]

[tex]x_1 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{8 - sqrt{88}}{4} = -0.35[/tex]

Time is positive, so it lands on the ground after 4.35 seconds.

A similar problem is given at https://brainly.com/question/17987697

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Rewritten by : Barada

Final answer:

The motion of the toy rocket is modeled by the equation h = -4(t-2)^2 + 14. Solving this equation results in the rocket landing at t = 3 seconds after launch.

Explanation:

The subject area of this problem is mathematics, particularly about studying the motions in a vertical line or free fall. The problem involves a toy rocket that is launched vertically and then returns to the ground. We can model this motion using a quadratic equation which fits the key stages of the rocket's path.

Let's denote the height of the rocket as h (in feet) and time as t (in seconds). Since the rocket initially launches from a height of 3 feet and reaches a maximum height of 11 feet in 2 seconds, our equation will look like: h = -4(t-2)^2 + 11 + 3.

To find out when the toy rocket will land, we need to set h to 0 and solve for t: 0 = -4(t-2)^2 + 14. After simplifying and taking the positive root, we find t = 3 seconds.

Learn more about Mathematical Modeling here:

https://brainly.com/question/30517381

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