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Answer :
To find the time when the water balloon hitting the ground, we need to set the given function equal to 0, solve for t, and discard the negative solution.
The given function h(t)=16t2+59 models the height of the water balloon at time t. To find the time when the water balloon hits the ground, we need to find the value of t when the height is 0. We can set the function equal to 0 and solve for t:
0 = 16t2 + 59
Subtracting 59 from both sides:
16t2 = -59
Dividing both sides by 16:
t2 = -59/16
Taking the square root of both sides:
t = ±â(-59/16)
Since time cannot be negative, we discard the negative solution. Therefore, the water balloon hits the ground at approximately t = â(-59/16) seconds.
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