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How many oxygen atoms are in 4.3 moles of Sn(OH)₄?

Answer :

1.04 × 10²⁵ oxygen atoms are in 4.3mols of Sn(OH)₄.

The Number of Oxygen Atoms per Molecule: Since there are four hydroxide groups in one molecule of Sn(OH)₄, each molecule contains four oxygen atoms.

Determine the Total Oxygen Atoms in 4.3 Moles:

The total number of oxygen atoms, we can use Avogadro's number, which states that 1 mole of any substance contains approximately 6.022 × 10²³ entities (atoms, molecules, etc.).

  • For 4.3 moles of Sn(OH)₄:

Total oxygen atoms = Number of moles × Number of O atoms per molecule × Avogadro's number

Total oxygen atoms = 4.3 moles × 4 O atoms/molecule × 6.022 × 10²³ atoms/mole

Total oxygen atoms = 4.3 × 4 × 6.022 × 10²³

Total oxygen atoms = 103.58 × 10²³

Total oxygen atoms ≈ 1.04 × 10²⁵ atoms.

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