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Find the derivative of the function f(x)=(x4−3x3+x)5/2 f′(x)=25​(4x3−9x2+1)3/2f′(x)=25​(x4−3x3+x)5/2(4x3−9x2+1)f′(x)=25​(x4−3x3+x)3/2(4x3−9x2+1)​ None of these. f′(x)=25​(x4−3x3+x)3/2 f′(x)=25​(4x3−9x2+1)5/2

Answer :

The derivative of the function f(x) = √(x⁴ - 3x³ + x)⁵ is given by f'(x) = (5/2) × √(x⁴ - 3x³ + x)³ × (4x³ - 9x² + 1).

To find the derivative of the function f(x) = √(x⁴ - 3x³ + x)⁵, we can use the chain rule and the power rule of differentiation. Let's proceed step by step:

Step 1: Rewrite the function using the exponentiation notation:

f(x) = √(x⁴ - 3x³ + x)⁵

Step 2: Apply the chain rule by differentiating the outer function with respect to the inner function:

f'(x) = (5/2) × (x⁴ - 3x³ + x[tex])^{\frac{5}{2} - 1 }[/tex]× d/dx (x⁴ - 3x³ + x)

Step 3: Differentiate the inner function, which involves applying the power rule:

f'(x) = (5/2) × √(x⁴ - 3x³ + x)³ × (4x³ - 9x² + 1)

Therefore, the derivative of the function f(x) = √(x⁴ - 3x³ + x)⁵ is given by f'(x) = (5/2) × √(x⁴ - 3x³ + x)³ × (4x³ - 9x² + 1).

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The complete question is:

Find the derivative of the function f(x)= √(x⁴ − 3x³ + x)⁵

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