High School

We appreciate your visit to A student combined 37 2 mL of a 1 69 M KMnO₄ solution with 16 20 mL of a 0 891 M KMnO₄ solution Calculate. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A student combined 37.2 mL of a 1.69 M KMnO₄ solution with 16.20 mL of a 0.891 M KMnO₄ solution. Calculate the concentration of the final solution.

Answer :

Final answer:

The concentration of the final KMnO4 solution is calculated by first finding the total number of moles in the initial solutions and then dividing by the total volume. After these calculations, the final concentration comes out to be approximately 1.447 M.

Explanation:

In order to calculate the concentration of the final solution, we start by calculating the number of moles in each solution using the formula molarity = moles ÷ volume. For the first solution, the number of moles = volume x molarity = 37.2 ml x 1.69 M = 62.878 moles. Similarly, for the second solution, the number of moles = 16.20 ml x 0.891 M = 14.4306 moles. Therefore, the total moles in the final solution = 62.878 moles + 14.4306 moles = 77.3086 moles. The total volume of the final solution = 37.2 ml + 16.20 ml = 53.4 ml. Hence, the molarity or the concentration in the final solution = total moles ÷ total volume = 77.3086 moles ÷ 53.4 ml = 1.447 M.

Learn more about Final Concentration here:

https://brainly.com/question/31384811

#SPJ11

Thanks for taking the time to read A student combined 37 2 mL of a 1 69 M KMnO₄ solution with 16 20 mL of a 0 891 M KMnO₄ solution Calculate. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada