We appreciate your visit to By titration 15 0 mL of 0 1008 M sodium hydroxide is needed to neutralize a 0 1331 g sample of a weak acid What. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The molar mass of the monoprotic acid is 88.06 g/mol.
Explanation:
To determine the molar mass of the monoprotic acid, we need to calculate the number of moles of the acid that reacted with the sodium hydroxide. From the titration, we know that 15.0 ml of 0.1008 M sodium hydroxide was needed to neutralize the acid. Using the equation for the reaction:
Acid + NaOH -> Salt + Water
We can construct a conversion factor:
0.1008 mol NaOH/1 L NaOH * 0.015 L NaOH = 0.001512 mol NaOH
Since the acid is monoprotic, 1 mol of the acid reacts with 1 mol of NaOH. Therefore, the molar mass of the acid is:
0.1331 g Acid / 0.001512 mol = 88.06 g/mol
Thanks for taking the time to read By titration 15 0 mL of 0 1008 M sodium hydroxide is needed to neutralize a 0 1331 g sample of a weak acid What. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
