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A toy rocket is launched vertically from a pad 8 feet above the ground with an initial velocity of 32 feet per second. The height \( h \), in feet, of the rocket above the ground at \( t \) seconds after launch is given by the function \( h(t) = -16t^2 + 32t + 8 \).

1. How long will it take the rocket to reach its maximum height?

The rocket reaches its maximum height at \(\_\_\_\) seconds after launch. (Simplify your answer.)

2. What is the maximum height?

The maximum height reached by the rocket is \(\_\_\_\) feet. (Simplify your answer.)

Answer :

Final Answer:

The rocket will reach its maximum height in 1 second, reaching a maximum height of 24 feet.

Explanation:

The height of the rocket above the ground at time t seconds after launch is given by the function h(t) = -16t² + 32t + 8. To find the time it takes for the rocket to reach its maximum height, we need to determine when the rocket's vertical velocity becomes zero. The rocket's vertical velocity is given by the derivative of the height function with respect to time: v(t) = h'(t) = -32t + 32.

Setting v(t) = 0 and solving for t:

-32t + 32 = 0

-32t = -32

t = 1 second.

So, it takes the rocket 1 second to reach its maximum height. To find the maximum height, we substitute this time back into the height function:

h(1) = -16(1)² + 32(1) + 8

h(1) = -16 + 32 + 8

h(1) = 24 feet.

Therefore, the rocket reaches its maximum height of 24 feet after 1 second.

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