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In 2012, the world's largest pumpkin weighed 913 kilograms. An average-sized pumpkin weighs 5,000 grams.

The 2012 world-record pumpkin weighs _____ kilograms more than an average-sized pumpkin.

Answer :

Final answer:

The 2012 world-record pumpkin, weighing 913 kilograms, is 908 kilograms heavier than an average-sized pumpkin, which weighs 5 kilograms.

Explanation:

The 2012 world-record pumpkin weighs 913 kilograms, which is significantly more than an average-sized pumpkin. An average-sized pumpkin weighs 5,000 grams. To compare the weights of the two pumpkins in the same units, we need to convert the average pumpkin's weight into kilograms. Since there are 1,000 grams in 1 kilogram, an average pumpkin weighs 5,000 grams / 1,000 = 5 kilograms.

Now, we can calculate the difference in weight between the two pumpkins:

913 kg (world-record pumpkin) - 5 kg (average pumpkin) = 908 kg

Therefore, the 2012 world-record pumpkin weighs 908 kilograms more than an average-sized pumpkin.

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Rewritten by : Barada

Final answer:

The 2012 world-record pumpkin weighs 908,000 grams more than an average-sized pumpkin, which is equivalent to 908 kilograms more.

Explanation:

To find the weight difference between the world-record pumpkin and an average-sized pumpkin, we need to subtract the weight of the average-sized pumpkin from the weight of the world-record pumpkin. The world-record pumpkin weighed 913 kilograms, which is the same as 913,000 grams. So, the weight of the world-record pumpkin is 913,000 grams. An average-sized pumpkin weighs 5,000 grams. To find the weight difference, we subtract 5,000 grams from 913,000 grams. 913,000 - 5,000 = 908,000 grams. Therefore, the 2012 world-record pumpkin weighs 908,000 grams more than an average-sized pumpkin, which is equivalent to 908 kilograms more.