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Answer :
The molar mass of a 98.2 g sample of gas that fills a 50.0-liter container at STP will be 44.0 g/mol. Option B is correct.
The ideal gas law equation will be: PV = nRT
where:
P is pressure, V is volume, n is the number of moles, R will be the gas constant, and T is the temperature.
At STP, the pressure will be 1 atm and the temperature will be 273 K.
To find the molar mass of the gas, we first need to calculate the number of moles of the gas present in the container. We will use the ideal gas law to solve for number of moles:
n = PV/RT
Substituting the values we know:
n = (1 atm)(50.0 L)/(0.08206 L atm/mol K)(273 K)
n = 2.03 mol
Next, we can use the definition of molar mass to calculate it:
molar mass = mass / moles
molar mass = 98.2 g / 2.03 mol
molar mass = 48.3 g/mol
Therefore, the closest answer is 44.0 g/mol, but the actual molar mass is slightly higher.
Hence, B. 44.0 g/mol is the correct option.
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