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A 1,135 kg car starts from rest. A constant force of 395 N acts on it. What is the distance (in meters) it travels in 3.1 seconds?

Answer :

Final answer:

The car, subject to a constant force of 395 N and with a mass of 1,135 kg, accelerates at 0.348 m/s² and travels a distance of 1.688 meters in 3.1 seconds.

Explanation:

To calculate the distance a car travels under a constant force, we can use the formula of motion from physics. First, we find the acceleration using the formula a = F / m, where a is the acceleration, F is the force applied, and m is the mass of the car. For a 1,135 kg car with a constant force of 395 N acting on it, the acceleration is calculated as follows:

a = 395 N / 1,135 kg = 0.348 m/s²

Next, we use the formula s = ut + 1/2 at², where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time. Since the car starts from rest, u = 0, thus the formula simplifies to s = 1/2 at². Plugging in the values:

s = 1/2 × 0.348 m/s² × (3.1 s)²

s = 1.688 m

Therefore, the car travels a distance of 1.688 meters in 3.1 seconds under a constant force of 395 N.

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