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Answer :
Final answer:
Using the work-energy principle in Physics, quadrupling the initial velocity of a 4.3 kg block sliding on a horizontal plane from 3.6 m/s results in a stopping distance of 32 meters.
Explanation:
The question involves the concepts of kinematics and work-energy principle in Physics. Given a mass undergoing deceleration due to friction on a horizontal surface, we can calculate the block's stopping distance when its initial velocity is quadrupled.
To solve the problem, we first identify that the work done by friction is the change in kinetic energy of the block. Since the distance is proportional to the square of the velocity when work is constant, quadrupling the initial velocity would increase the stopping distance by a factor of sixteen. Thus, if the initial velocity were quadrupled from 3.6 m/s to 14.4 m/s, the block would slide 2 m * 16 = 32 m before coming to a stop.
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