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Answer :
The solubility product constant (Ksp) for potassium iodate (KIO3) with a solubility of 38.8 g/L at a certain temperature is approximately 3.29 x 10^-2.
To calculate the solubility product constant (Ksp) for potassium iodate (KIO3), which has a solubility of 38.8 g/L at a certain temperature, we first need to convert this solubility into molarity. Potassium iodate dissociates into K+ and IO3- ions in solution. Since the molar mass of KIO3 is 214 g/mol, the molarity is 38.8 g/L divided by 214 g/mol, yielding approximately 0.1815 M. As each KIO3 molecule produces one K+ and one IO3-, the molar concentrations of these ions will be the same as the molarity of KIO3. The solubility product constant is then the product of the concentrations of these ions, or (0.1815)(0.1815), which equals approximately 3.29 x 10-2. Therefore, the Ksp for potassium iodate is 3.29 x 10-2 at this temperature.
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