High School

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Tiara wants to paint each wall of her bedroom a different color. She needs two quarts of paint for each wall. Each quart costs [tex]\(\$11\)[/tex]. She also needs to buy two paintbrushes for [tex]\(\$3\)[/tex] each. She pays with a [tex]\(\$100\)[/tex] bill. How much change does Tiara get? Show your work.

**Solution:**

1. Cost of one quart of paint = [tex]\(\$11\)[/tex]
2. Cost for two quarts per wall: [tex]\(2 \times 11 = \$22\)[/tex]
3. Total cost for four walls: [tex]\(4 \times 22 = \$88\)[/tex]
4. Cost of two paintbrushes: [tex]\(2 \times 3 = \$6\)[/tex]
5. Total cost: [tex]\(\$88 + \$6 = \$94\)[/tex]
6. Change from [tex]\(\$100\)[/tex]: [tex]\(\$100 - \$94 = \$6\)[/tex]

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Chris can walk 5 kilometers in 60 minutes. That is 3 times as long as it takes Alden to run the same distance. How many more minutes does it take Chris to walk 5 kilometers than it takes Alden to run the same distance? Show your work.

**Solution:**

1. Time for Chris to walk 5 km = 60 minutes
2. Alden's time to run the same distance = [tex]\(\frac{60}{3} = 20\)[/tex] minutes
3. Difference in time = [tex]\(60 - 20 = 40\)[/tex] minutes

Answer :

Let's solve the problem step-by-step:

1. Chris's Time to Walk 5 Kilometers:
- We know Chris takes 60 minutes to walk 5 kilometers.

2. Alden's Time to Run 5 Kilometers:
- We're told that it takes Chris 3 times as long as it takes Alden to run the same distance.
- To find out how long it takes Alden, we divide Chris's time by 3:
[tex]\[
\text{Alden's time} = \frac{60 \text{ minutes}}{3} = 20 \text{ minutes}
\][/tex]

3. Difference in Time:
- To find the difference in time between Chris walking and Alden running, we subtract Alden’s time from Chris’s time:
[tex]\[
\text{Time difference} = 60 \text{ minutes} - 20 \text{ minutes} = 40 \text{ minutes}
\][/tex]

So, it takes Chris 40 more minutes to walk 5 kilometers than it takes Alden to run the same distance.

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