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My neighbor's lawn is a similar shape to mine but has dimensions [tex]\frac{2}{3}[/tex] as large. I used 90 kg of ammonium sulfate to treat my lawn. How much would he need to treat his own lawn in the same way?

A. 120 kg
B. 60 kg
C. 135 kg
D. 40 kg

Answer :

Final answer:

Given that the neighbor's lawn is 2/3 the size of the student's lawn, it would require 2/3 the amount of ammonium sulfate to treat, which calculates to 60kg.

Explanation:

The question is about the proportional relationship between two similar lawns and the amounts of ammonium sulfate needed to treat each. The student's lawn, which is larger, was treated with 90kg of ammonium sulfate. We know that the neighbor's lawn is 2/3 the size of the student's, which means it should require 2/3 the amount of ammonium sulfate.

Using this information, we can set up a simple calculation: 90kg (the amount used for the larger lawn) * 2/3 (the size ratio of the smaller lawn) = 60kg. Therefore, the neighbor would need 60kg of ammonium sulfate to treat his lawn in the same way.

Learn more about Proportional Relationships here:

https://brainly.com/question/29765554

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