High School

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Josiah invests [tex]\$360[/tex] into an account that accrues [tex]3\%[/tex] interest annually. Assuming no deposits or withdrawals are made, which equation represents the amount of money in Josiah's account, [tex]y[/tex], after [tex]x[/tex] years?

A. [tex]y = 360(1.3)^x[/tex]

B. [tex]y = 360(0.3)^x[/tex]

C. [tex]y = 360(0.03)^x[/tex]

D. [tex]y = 360(1.03)^x[/tex]

Answer :

To solve the problem of determining the amount of money in Josiah's account after a certain number of years, we need to use the formula for compound interest. The formula for the amount [tex]\( y \)[/tex] in the account after [tex]\( x \)[/tex] years is given by:

[tex]\[ y = P(1 + r)^x \][/tex]

where:
- [tex]\( P \)[/tex] is the principal amount (the initial investment),
- [tex]\( r \)[/tex] is the annual interest rate (expressed as a decimal),
- [tex]\( x \)[/tex] is the number of years.

In this problem:
- The principal [tex]\( P \)[/tex] is $360.
- The annual interest rate [tex]\( r \)[/tex] is 3%, which is 0.03 as a decimal.
- We need to find the expression for [tex]\( y \)[/tex] after [tex]\( x \)[/tex] years.

Plug these values into the formula:

[tex]\[ y = 360(1 + 0.03)^x \][/tex]

[tex]\[ y = 360(1.03)^x \][/tex]

This equation represents the amount of money in Josiah's account after [tex]\( x \)[/tex] years, where the account accrues a 3% interest annually. Looking at the options, the correct equation is:

[tex]\[ y = 360(1.03)^x \][/tex]

Therefore, the equation [tex]\( y = 360(1.03)^x \)[/tex] is the correct representation of the amount of money in Josiah's account after [tex]\( x \)[/tex] years.

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