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If the density of tin is 7.26 g/cm³, what is the thickness of a piece of tin foil that measures 5.00 cm by 5.00 cm and has a mass of 2.122 grams?

Answer :

Final answer:

To find the thickness of the tin foil, we rearrange the density formula to solve for thickness. After calculating the area of the tin foil, we divide the mass by the product of the area and the density, yielding a thickness of approximately 0.1168 millimeters.

Explanation:

To calculate the thickness of a piece of tin foil with a mass of 2.122 grams and a dimension of 5.00cm by 5.00cm given that the density of tin is 7.26 g/cm3, we will use the formula for density:

Density = Mass / Volume

Where volume, in the case of the foil, is the product of its length, width, and thickness. We already have the mass and the area (which is length times width).

The area of the foil (Length x Width) is 5.00cm x 5.00cm = 25.00 cm2. The volume is then:

Volume = Area x Thickness

Using the given density,

7.26 g/cm3 = 2.122 g / (25.00 cm2 x Thickness)

Now, solve for Thickness:

Thickness = 2.122 g / (25.00 cm2 x 7.26 g/cm3)

Thickness = 0.01168 cm or 0.1168 mm

Therefore, the thickness of the tin foil is approximately 0.1168 millimeters.

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