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Answer :
Final answer:
The percentage of women with weights between 1488 lb and 208 lb is approximately 21.19%. No women are excluded with those specifications.
Explanation:
To find the percentage of women with weights within the limits of 1488 lb and 208 lb, we need to calculate the z-scores for these limits using the given mean and standard deviation.
For the lower limit of 208 lb:
z = (208 - 1652) / 428 = -1.08
For the upper limit of 1488 lb:
z = (1488 - 1652) / 428 = -0.38
Now, we can refer to a standard normal distribution table or use a calculator to find the percentage of data within these z-scores.
According to the standard normal distribution table, the percentage of data within a z-score of -1.08 is approximately 0.1401, and the percentage of data within a z-score of -0.38 is approximately 0.3520.
Therefore, the percentage of women with weights between 1488 lb and 208 lb is:
0.3520 - 0.1401 = 0.2119, or 21.19% (rounded to two decimal places).
Based on these specifications, no women are excluded as the percentage is greater than 0%.
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