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Answer :
The current through the lamp when it is lit is 1.22 A. The current through the lamp can be calculated using Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the resistance (R). In this case, the resistance of the lamp can be found using the power formula, P = IV, where P is the power in watts.
First, we need to find the resistance of the lamp. Given that the power of the lamp is 146 W, we can rearrange the power formula to solve for resistance: R = P / I. Since we are looking for the current (I), we rearrange Ohm's Law to solve for current: I = V / R.
The voltage (V) is given as 120 V. Plugging in the values, we get I = 120 V / (146 W / I). To solve for I, we can cross-multiply: I * (146 W / I) = 120 V. The current (I) cancels out, leaving us with 146 W = 120 V.
Simplifying further, we find I = 146 W / 120 V. Evaluating this expression, the current through the lamp when it is lit is approximately 1.22 A.
Learn more about Ohm's Law here,
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