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Answer :
Final answer:
To prepare 2.00 L of 0.108 M BaCl₂ - 2H₂O, dissolve 52.8 g of the compound in water and dilute the solution to a total volume of 2.00 L.
Explanation:
In order to prepare a 2.00 L solution of 0.108 M BaCl₂ - 2H₂O, you'll need to dissolve a certain amount of BaCl₂ - 2H₂O in water and then dilute it to the desired volume. The molarity (M) given is used to calculate the amount of BaCl₂ - 2H₂O needed through the equation M = moles of solute / volume of solution in liters. Given that the molar mass of BaCl₂ - 2H₂O is 244.3 g/mol, the calculation results in approximately 52.8 g of BaCl₂ - 2H₂O needed. This solid must then be dissolved in a volume of water less than 2.00 L, then dilute the solution by adding more water until the overall volume is 2.00 L.
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