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Answer :
Sure! Let’s work through the problem together step-by-step.
### Problem Analysis:
We are given:
- Long wings (W) are dominant to short wings (w).
- Two homozygous recessive flies are crossed.
### Step-by-Step Solution:
1. Identifying the Genotypes:
- Homozygous recessive flies have the genotype ww (since “homozygous” means having two identical alleles, and "recessive" means the allele in question is w).
2. Crossing the Flies:
- When two homozygous recessive flies (ww and ww) are crossed, every offspring will receive one w allele from each parent.
- Therefore, all offspring will have the ww genotype.
3. Determining the Phenotypes:
- The phenotype (observable trait) is dictated by the genotype.
- Since ww is the genotype for short wings, all offspring will exhibit short wings.
4. Calculating the Probabilities:
- Since 100% of the offspring have the ww genotype, 100% of them will exhibit short wings.
- Additionally, there is no chance (0%) for any offspring to have long wings because none of them have the dominant allele W.
### Summary of Probabilities:
- Probability of Long Wings: 0% (since no offspring have the W allele).
- Probability of Short Wings: 100% (since all offspring have the ww genotype).
This means:
- Long Wings: 0%
- Short Wings: 100%
These calculations confirm that all offspring will have short wings, and none will have long wings.
### Problem Analysis:
We are given:
- Long wings (W) are dominant to short wings (w).
- Two homozygous recessive flies are crossed.
### Step-by-Step Solution:
1. Identifying the Genotypes:
- Homozygous recessive flies have the genotype ww (since “homozygous” means having two identical alleles, and "recessive" means the allele in question is w).
2. Crossing the Flies:
- When two homozygous recessive flies (ww and ww) are crossed, every offspring will receive one w allele from each parent.
- Therefore, all offspring will have the ww genotype.
3. Determining the Phenotypes:
- The phenotype (observable trait) is dictated by the genotype.
- Since ww is the genotype for short wings, all offspring will exhibit short wings.
4. Calculating the Probabilities:
- Since 100% of the offspring have the ww genotype, 100% of them will exhibit short wings.
- Additionally, there is no chance (0%) for any offspring to have long wings because none of them have the dominant allele W.
### Summary of Probabilities:
- Probability of Long Wings: 0% (since no offspring have the W allele).
- Probability of Short Wings: 100% (since all offspring have the ww genotype).
This means:
- Long Wings: 0%
- Short Wings: 100%
These calculations confirm that all offspring will have short wings, and none will have long wings.
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Rewritten by : Barada
The cross of two homozygous recessive flies (ww x ww) will result in 100% short-winged offspring (ww). There is a 0% probability of long-winged offspring.
A homozygous recessive individual has two copies of the recessive allele (ww). When two homozygous recessive individuals are crossed, each parent can only contribute the recessive allele (w) to their offspring. This means that every possible combination of alleles in the offspring will be ww.
Since short wings (w) are recessive, any individual with the ww genotype will exhibit the short-winged phenotype. Therefore, the probability of long wings (W) is 0%, and the probability of short wings (w) is 100%. The cross of two homozygous recessive individuals will always result in homozygous recessive offspring, as there are no dominant alleles present to mask the recessive trait.
Complete question:
In flies, long wings (W) are dominant to short wings (w). Two homozygous recessive flies are crossed. Homozygous Recessive Fly Phenotype Probability (%) WLong Wings: 0% w Short Wings: 0%
