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Answer :
To find out how many moles are in 98.3 grams of aluminum hydroxide, [tex]\( \text{Al(OH)}_3 \)[/tex], we need to follow these steps:
1. Determine the molar mass of [tex]\( \text{Al(OH)}_3 \)[/tex]:
- Aluminum (Al) has an atomic mass of approximately 26.98 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol.
- Hydrogen (H) has an atomic mass of approximately 1.01 g/mol.
2. Calculate the molar mass of [tex]\( \text{Al(OH)}_3 \)[/tex]:
- There is one aluminum atom in [tex]\( \text{Al(OH)}_3 \)[/tex]: [tex]\( 1 \times 26.98 = 26.98 \, \text{g/mol} \)[/tex]
- There are three oxygen atoms: [tex]\( 3 \times 16.00 = 48.00 \, \text{g/mol} \)[/tex]
- There are three hydrogen atoms: [tex]\( 3 \times 1.01 = 3.03 \, \text{g/mol} \)[/tex]
Add these together to get the molar mass of [tex]\( \text{Al(OH)}_3 \)[/tex]:
[tex]\[
26.98 + 48.00 + 3.03 = 78.01 \, \text{g/mol}
\][/tex]
3. Calculate the number of moles of [tex]\( \text{Al(OH)}_3 \)[/tex]:
To find the number of moles, use the formula:
[tex]\[
\text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}}
\][/tex]
Given the mass of [tex]\( \text{Al(OH)}_3 \)[/tex] is 98.3 grams, we can calculate the number of moles:
[tex]\[
\text{Number of moles} = \frac{98.3 \, \text{g}}{78.01 \, \text{g/mol}}
\][/tex]
[tex]\[
\text{Number of moles} \approx 1.26
\][/tex]
Therefore, there are approximately 1.26 moles in 98.3 grams of [tex]\( \text{Al(OH)}_3 \)[/tex].
1. Determine the molar mass of [tex]\( \text{Al(OH)}_3 \)[/tex]:
- Aluminum (Al) has an atomic mass of approximately 26.98 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol.
- Hydrogen (H) has an atomic mass of approximately 1.01 g/mol.
2. Calculate the molar mass of [tex]\( \text{Al(OH)}_3 \)[/tex]:
- There is one aluminum atom in [tex]\( \text{Al(OH)}_3 \)[/tex]: [tex]\( 1 \times 26.98 = 26.98 \, \text{g/mol} \)[/tex]
- There are three oxygen atoms: [tex]\( 3 \times 16.00 = 48.00 \, \text{g/mol} \)[/tex]
- There are three hydrogen atoms: [tex]\( 3 \times 1.01 = 3.03 \, \text{g/mol} \)[/tex]
Add these together to get the molar mass of [tex]\( \text{Al(OH)}_3 \)[/tex]:
[tex]\[
26.98 + 48.00 + 3.03 = 78.01 \, \text{g/mol}
\][/tex]
3. Calculate the number of moles of [tex]\( \text{Al(OH)}_3 \)[/tex]:
To find the number of moles, use the formula:
[tex]\[
\text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}}
\][/tex]
Given the mass of [tex]\( \text{Al(OH)}_3 \)[/tex] is 98.3 grams, we can calculate the number of moles:
[tex]\[
\text{Number of moles} = \frac{98.3 \, \text{g}}{78.01 \, \text{g/mol}}
\][/tex]
[tex]\[
\text{Number of moles} \approx 1.26
\][/tex]
Therefore, there are approximately 1.26 moles in 98.3 grams of [tex]\( \text{Al(OH)}_3 \)[/tex].
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